Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter R - Section R.1 - Factors and the Least Common Multiple - Exercise Set - Page R-7: 23

Answer

$20 = 2\cdot 2\cdot 5$

Work Step by Step

The $\textit{prime factorization}$ of a number is obtained by writing the number as a product of primes. To determine the prime factorization of $20$ we write the number as a product of factors and continue the process until all factors are prime numbers. We start by writing $20$ as a product of two numbers: $20=2\cdot 10$. The number $2$ is prime, but $10$ is not. So we write $10=2\cdot 5$: $20=2\cdot 2\cdot 5$. Now each factor is a prime number, therefore the prime factorization of $20$ is $2\cdot 2\cdot 5$.
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