Algebra: A Combined Approach (4th Edition)

Published by Pearson
ISBN 10: 0321726391
ISBN 13: 978-0-32172-639-1

Chapter R - Section R.1 - Factors and the Least Common Multiple - Exercise Set - Page R-7: 33

Answer

Option $d$

Work Step by Step

We determine the factors of $48$. $48=1\cdot 48=2\cdot 24=3\cdot 16=4\cdot 12=6\cdot 8$. Therefore the factors of $48$ are: $1,2,3,4,6,8,12,16,24,48$ The correct answer is option $d$.
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