Answer
$64 = 2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 2$
Work Step by Step
The $\textit{prime factorization}$ of a number is obtained by writing the number as a product of primes.
To determine the prime factorization of $64$ we write the number as a product of factors and continue the process until all factors are prime numbers.
We start by writing $64$ as a product of two numbers:
$64=2\cdot 32$.
The number $2$ is prime, but $32$ is not. So we write $32=2\cdot 16$:
$64=2\cdot 2\cdot 16$.
As $16$ is not a prime number we write: $16=2\cdot 8$ and we have:
$64=2\cdot 2\cdot 2\cdot 8$.
As $8$ is not a prime number we write: $8=2\cdot 4$ and we have:
$64=2\cdot 2\cdot 2\cdot 2\cdot 4$.
As $4$ is not a prime number we write: $4=2\cdot 2$ and we have:
$64=2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 2$.
Now each factor is a prime number, therefore the prime factorization of $64$ is $2\cdot 2\cdot 2\cdot 2\cdot 2\cdot 2$.
