Answer
No Solution
Work Step by Step
Solve : $ 2 \div ((x-4)(x-2)) = 1/(x-4) + 2/(x-2) $
$ 2 \div ((x-4)(x-2)) = (x-2 + 2(x-4) ) \div ((x-4)(x-2))$
2 = x - 2 + 2x -8
2 = 3x - 10
3x = 12
x=4
Plug in the x=4 and the denominator becomes zero and since division by zero is not defined, x=4 is an extraneous solution.
