Answer
x =$\frac{7}{4}$
Work Step by Step
Solve : $\frac{1}{x-2} + \frac{3}{x+3} = \frac{4}{x^{2} + x -6}$
$\frac{1}{x-2} + \frac{3}{x+3} = \frac{4}{(x-2)(x+3)}$
Multiplying both sides with (x-2)(x+3)
x+3 + 3(x-2) = 4
x+3+3x-6 = 4
4x = 7
x =$\frac{7}{4}$
