Answer
No solution
Work Step by Step
$x\ne1,-3$ because the denominators cannot be equal to $0$.
After multiplying both sides by $(x-1)(x+3):$
$12=3(x+3)+2(x-1)\\12=3x+9+2x-2\\12=5x+7\\5=5x\\x=1$
But $x\ne1$ from earlier. Thus there is no solution.
