Answer
x = 5
Work Step by Step
Solve : $ \frac{1}{x-3} + \frac{1}{x+3} = \frac{10}{x^{2}-9}$
$ \frac{x+3}{x^{2}-9} + \frac{x-3}{x^{2}-9} = \frac{10}{x^{2}-9}$ as (x+3)(x-3) = ${x^{2}-9}$
x+3 + x-3 = 10
2x = 10
x = 5
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Chapter 1 - 1.2 - Linear Equations in One Variable - 1.2 Exercises - Page 87: 41
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