Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Prerequisites - P.2 - Exponents and Radicals - Exercises - Page 24: 20

Answer

$\dfrac{4}{9}$

Work Step by Step

Need to solve $12(-x)^3$ Plug the value of $x=-\dfrac{1}{3}$ in $12(-x)^3$ $12(-x)^3=12[-(-\dfrac{1}{3})]^3$ and $(12) \cdot (\dfrac{1}{27})=\dfrac{4}{9}$
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