Algebra and Trigonometry 10th Edition

Published by Cengage Learning
ISBN 10: 9781337271172
ISBN 13: 978-1-33727-117-2

Prerequisites - P.2 - Exponents and Radicals - Exercises - Page 24: 39

Answer

a) $3$ b) $1.5$

Work Step by Step

a) $\sqrt9=3$ b) $\sqrt[3] {\frac{27}{8}}=\sqrt[3] {\frac{3^3}{2^3}}=\frac{3}{2}=1.5$
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