Answer
a) $\frac{x^2}{y^2}$
b) $1$
Work Step by Step
a) $[(x^2y^{-2})^{-1}]^{-1}=\frac{1}{(x^2y^{-2})^{-1}}=x^2y^{-2}=\frac{x^2}{y^2}$
b) $(5x^2z^6)^3(5x^2z^6)^{-3}=\frac{(5x^2z^6)^3}{(5x^2z^6)^3}=1$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - P.2 - Exponents and Radicals - Exercises - Page 24: 26
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