Answer
a) $\frac{1}{9}$
b) $\frac{1}{x}$
Work Step by Step
a) $\frac{3^n3^{2n}}{3^{3n}3^2}=\frac{3^{n+2n}}{3^{3n}3^2}=\frac{3^{3n}}{3^{3n}3^2}=\frac{1}{3^2}=\frac{1}{9}$
b) $\frac{x^2x^n}{x^3x^n}=\frac{x^2}{x^3}=\frac{1}{x}$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - P.2 - Exponents and Radicals - Exercises - Page 24: 30
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