Answer
$ (2t-1)(4t^{2}+2t + 1)$
Work Step by Step
Expression : $8t^{3}-1$
By the well known formula : $x^{3}-y^{3}=(x-y)(x^{2}+xy+y^{2})$
Hence, $8t^{3}-1 = (2t)^{3}-1^{3} = (2t-1)((2t)^{2}+2t(1) + 1^{2}) = (2t-1)(4t^{2}+2t + 1)$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - p.4 - Factoring Polynomials - Exercises - Page 39: 27
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