Answer
$(3y-\frac{1}{4})^2$
Work Step by Step
$9y^2-\frac{3}{2}y+\frac{1}{16}=(3y)^2-2(3y)(\frac{1}{4})+(\frac{1}{4})^2=(3y-\frac{1}{4})^2$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - p.4 - Factoring Polynomials - Exercises - Page 39: 74
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