Answer
$(x+1)(x+3)(x-1)(x-3)$
Work Step by Step
Use: $4x=3x+x$ and $-4x=-3x-x$
$(x^2+3)^2-16x^2=(x^2+3)^2-(4x)^2=(x^2+3+4x)(x^2+3-4x)=(x^2+3x+x+3)(x^2-3x-x+3)=[x(x+3)+1(x+3)][x(x-3)-1(x-3)]=(x+1)(x+3)(x-1)(x-3)$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - p.4 - Factoring Polynomials - Exercises - Page 39: 61
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