Answer
$(y+\frac{2}{3})(y^2-\frac{2y}{3}+\frac{4}{9})$
Work Step by Step
$y^3+\frac{8}{27}=y^3+(\frac{2}{3})^3=(y-\frac{2}{3})[y^2+y(\frac{2}{3})+(\frac{2}{3})^2]=(y+\frac{2}{3})(y^2-\frac{2y}{3}+\frac{4}{9})$
Algebra and Trigonometry 10th Edition
by Larson, Ron
Published by
Cengage Learning
ISBN 10:
9781337271172
ISBN 13:
978-1-33727-117-2
Prerequisites - p.4 - Factoring Polynomials - Exercises - Page 39: 75
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