College Algebra (10th Edition)

Published by Pearson
ISBN 10: 0321979478
ISBN 13: 978-0-32197-947-6

Chapter R - Section R.8 - nth Roots; Rational Exponents - R.8 Assess Your Understanding - Page 80: 105

Answer

$(x^{2}+4)^{1/3}(11x^{2}+12)$

Work Step by Step

We simplify: $3(x^{2}+4)^{4/3}+x* 4(x^{2}+4)^{1/3}*2x =(x^{2}+4)^{1/3}[3(x^{2}+4)^{3/3}+4*2x^{2}] =(x^{2}+4)^{1/3}[3(x^{2}+4)+8x^{2}] =(x^{2}+4)^{1/3}[3x^{2}+12+8x^{2}] =(x^{2}+4)^{1/3}(11x^{2}+12)$
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