Answer
$\displaystyle \frac{8x-4}{x^{2/3}}
=\frac{4(2x-1)}{x^{2/3}}$
Work Step by Step
We simplify:
$\displaystyle 8x^{1/3}-4x^{-2/3}
=8x^{1/3}-\frac{4}{x^{2/3}}
=8x^{1/3}*\frac{x^{2/3}}{x^{2/3}}-\frac{4}{x^{2/3}}
=\frac{8x^{1/3}\cdot x^{2/3}-4}{x^{2/3}}
=\frac{8x^{3/3}-4}{x^{2/3}}
=\frac{8x-4}{x^{2/3}}
=\frac{4(2x-1)}{x^{2/3}}$
