Answer
(a) $v = 16$ ft/sec
(b) $v = 32$ ft/sec
(c) $v = 12$ ft/sec
Work Step by Step
We apply the given formula, where h is the height of the incline plane and $v_{0}$ is the initial velocity of the object:
$v = \sqrt{64h +v_{0}^{2}}$
(a) As given by the problem, $h = 4, v_{0} = 0$, so:
$v = \sqrt{64*4 +0^{2}}$ = $16$
(b) As given by the problem, $h = 16, v_{0} = 0$, so:
$v = \sqrt{64*16 +0^{2}}$ = $32$
(c) As given by the problem, $h = 2, v_{0} = 4$, so:
$v = \sqrt{64*2 +4^{2}}$ = $\sqrt{64*2 +16}$ = $12$
