Answer
$16x^4-81$
Work Step by Step
Using $(a+b)(a-b)=a^2-b^2$ or the special product of the sum and difference of like terms, the product of the given expression, $
(2x+3)(2x-3)(4x^2-9)
,$ is
\begin{array}{l}\require{cancel}
[(2x+3)(2x-3)](4x^2-9)
\\\\=
[(2x)^2-(3)^2](4x^2-9)
\\\\=
(4x^2-9)(4x^2-9)
\\\\=
(4x^2)^2-(9)^2
\\\\=
16x^4-81
.\end{array}