Answer
5$p^{2}$ - 12p - 6q + 4pq + 9
Work Step by Step
1. Square of a binomial
$[(2p - 3) + q]^{2}$ = $(2p - 3)^{2}$ + 2(2p - 3)(q) + $q^{2}$ = $(2p)^{2}$ + 2(2p)(-3) + $(-3)^{2}$ + 2(2p - 3)(q) + $q^{2}$
2. Solve exponents and multiply
$4p^{2}$ - 12p + 9 + 4pq - 6q + $q^{2}$
3. Add like terms
5$p^{2}$ - 12p - 6q + 4pq + 9
