Answer
$4z^{8}$ - 12$z^{4}$y + 9$y^{2}$
Work Step by Step
1. Square of a binomial
$(2z^{4} - 3y)^{2}$ = $(2z^{4})^{2}$ + 2(2$z^{4}$)(-3y) + $(-3y)^{2}$
2. Solve exponents and multiply
$4z^{8}$ - 12$z^{4}$y + 9$y^{2}$
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