College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Section R.6 - Rational Exponents - R.6 Exercises - Page 56: 25

Answer

$\frac{4n^7}{3m^7}$

Work Step by Step

Reduce the coefficients and subtract the exponents of m and n. $\frac{16m^{-5}n^4}{12m^2n^{-3}}=\frac{4}{3}m^{-5-2}n^{4-(-3)}$ Simplify. $\frac{16m^{-5}n^4}{12m^2n^{-3}}=\frac{4}{3}m^{-7}n^7$ Make the exponents of m positive. $\frac{16m^{-5}n^4}{12m^2n^{-3}}=\frac{4n^7}{3m^7}$
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