Answer
$\frac{3}{5a^3b^5}$
Work Step by Step
Reduce the coefficients and subtract the exponents of m and n.
$\frac{15a^{-5}b^{-1}}{25a^{-2}b^4}=\frac{3}{5}a^{-5(-2)}b^{-1-4}$
Simplify.
$\frac{15a^{-5}b^{-1}}{25a^{-2}b^4}=\frac{3}{5}a^{-3}b^{-5}$
Make the exponents positive.
$\frac{15a^{-5}b^{-1}}{25a^{-2}b^4}=\frac{3}{5a^3b^5}$
