College Algebra (11th Edition)

Published by Pearson
ISBN 10: 0321671791
ISBN 13: 978-0-32167-179-0

Chapter R - Section R.6 - Rational Exponents - R.6 Exercises - Page 56: 30

Answer

$\frac{9}{p^{11}}$

Work Step by Step

Apply the property of exponents given by: $(a^m)^n=a^{mn}$ $(3p^{-4})^2(p^3)^{-1}=3^2p^{-8}p^{-3}$ Add the exponents of m and simplify. $(3p^{-4})^2(p^3)^{-1}=9a^{-11}=\frac{9}{p^{11}}$
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