Answer
$\frac{2x^{3}}{y}$
Work Step by Step
$(8x^{-6}y^{3})^{\frac{1}{3}}$$(x^{\frac{5}{6}}y^{-\frac{1}{3}})^{6}$
= $(8^{\frac{1}{3}}x^{-6\times\frac{1}{3}}y^{3\times\frac{1}{3}})$$(x^{\frac{5}{6}\times6}y^{-\frac{1}{3}\times6})$
= ($ \sqrt[3] 8x^{-2} y$)($x^{5}y^{-2}$)
= ($ 2x^{-2 + 5} y^{1-2}$)
= $ 2x^{3} y^{-1}$
= $\frac{2x^{3}}{y}$
