College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.3 - Page 49: 79

Answer

$-y\sqrt[3]{2x}$

Work Step by Step

$$\sqrt[3]{54xy^3} - y\sqrt[3]{128x}$$ $$=\sqrt[3]{27y^3\times2x} - y\sqrt[3]{64\times2x}$$ $$=\sqrt[3]{27y^3}\times\sqrt[3]{2x} - y\times\sqrt[3]{64}\times\sqrt[3]{2x}$$ $$=3y\sqrt[3]{2x} - 4y\sqrt[3]{2x}$$ $$=(3y-4y)\sqrt[3]{2x}$$ $$=-y\sqrt[3]{2x}$$
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