Answer
${x^{3} y^{-2}}$ = $\frac{x^{3}}{y^{2}}$
Work Step by Step
$(\frac{x^{-\frac{5}{4}}y^{\frac{1}{3}}}{x^{-\frac{3}{4}}})^{-6}$
= $({x^{-\frac{5}{4} + \frac{3}{4}} y^{\frac{1}{3}}})^{-6}$
= $({x^{-\frac{2}{4}} y^{\frac{1}{3}}})^{-6}$
= $({x^{-\frac{2}{4}\times-6} y^{\frac{1}{3}\times-6}})$
= ${x^{3} y^{-2}}$
= $\frac{x^{3}}{y^{2}}$
