Answer
$9\sqrt[3]{3}$
Work Step by Step
$$3\sqrt[3]{24} + \sqrt[3]{81}$$ $$=3\sqrt[3]{8\times3} + \sqrt[3]{27\times3}$$ $$=(3\times2)\sqrt[3]{3} +3\sqrt[3]{3}$$ $$=6\sqrt[3]{3} + 3\sqrt[3]{3}$$ $$=(6+3)\sqrt[3]{3}$$ $$=9\sqrt[3]{3}$$
College Algebra (6th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-32178-228-3
ISBN 13:
978-0-32178-228-1
Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.3 - Page 49: 78
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