Answer
$\frac{x-1}{x+3}$
Work Step by Step
$(1-\frac{1}{x})(1-\frac{1}{x+1})(1-\frac{1}{x+2})(1-\frac{1}{x+3})=\frac{x-1}{x}\frac{x}{x+1}\frac{x+1}{x+2}\frac{x+2}{x+3}=\frac{x-1}{x+3}$
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