College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.6 - Page 88: 107

Answer

$\frac{x-1}{x+3}$

Work Step by Step

$(1-\frac{1}{x})(1-\frac{1}{x+1})(1-\frac{1}{x+2})(1-\frac{1}{x+3})=\frac{x-1}{x}\frac{x}{x+1}\frac{x+1}{x+2}\frac{x+2}{x+3}=\frac{x-1}{x+3}$
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