Answer
$\frac{x-y+1}{(x-y)^{2}}; x \ne y;$
Work Step by Step
$(x-y)^{-1} + (x-y)^{-2} $
$= \frac{1}{(x-y)} + \frac{1}{(x-y)^{2}} ; x \ne y;$ $[a^{-m} = \frac{1}{a^{m}}]$
Taking LCD,
$= \frac{x-y+1}{(x-y)^{2}}; x \ne y;$
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