College Algebra (6th Edition)

Published by Pearson
ISBN 10: 0-32178-228-3
ISBN 13: 978-0-32178-228-1

Chapter P - Prerequisites: Fundamental Concepts of Algebra - Exercise Set P.6 - Page 88: 111

Answer

See below.

Work Step by Step

We plug in $x=-3,-2,-1,0,1,2,3$ into the expression: $y=1-x^2=1-(-3)^2=1-9=-8$ $y=1-x^2=1-(-2)^2=1-4=-3$ $y=1-x^2=1-(-1)^2=1-1=0$ $y=1-x^2=1-0^2=1-0=1$ $y=1-x^2=1-1^2=1-1=0$ $y=1-x^2=1-2^2=1-4=-3$ $y=1-x^2=1-3^2=1-9=-8$
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