Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter R - Section R.3 - Exponents, Roots, and Order of Operations - R.3 Exercises - Page 30: 66

Answer

$8$

Work Step by Step

Using order of operations and the concepts of the absolute value of a number, the given expression, $ -4|2-4|+8\cdot2 ,$ simplifies to \begin{array}{l}\require{cancel} -4|-2|+16 \\\\= -4(2)+16 \\\\= -8+16 \\\\= 8 .\end{array}
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