Answer
$\frac{27}{92}$
Work Step by Step
We are given that $a=-3$, $b=64$, and $c=6$.
Therefore, $\frac{3c+a^{2}}{2b-6c}=\frac{3(6)+(-3)^{2}}{2(64)-6(6)}=\frac{18+9}{128-36}=\frac{27}{92}$.
Intermediate Algebra (12th Edition)
by Lial, Margaret L.; Hornsby, John; McGinnis, Terry
Published by
Pearson
ISBN 10:
0321969359
ISBN 13:
978-0-32196-935-4
Chapter R - Section R.3 - Exponents, Roots, and Order of Operations - R.3 Exercises - Page 30: 86
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