Intermediate Algebra (12th Edition)

Published by Pearson
ISBN 10: 0321969359
ISBN 13: 978-0-32196-935-4

Chapter R - Section R.3 - Exponents, Roots, and Order of Operations - R.3 Exercises - Page 30: 84

Answer

-261

Work Step by Step

We are given that $a=-3$, $b=64$, and $c=6$. Therefore, $-3a^{4}-3c=-3(-3)^{4}-3(6)=-3(81)-18=-243-18=-261$
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