Answer
-1
Work Step by Step
We are given that $a=-3$, $b=64$, and $c=6$.
Therefore, $\sqrt b-c+a=\sqrt 64-6+(-3)=8-6-3=2-3=-1$.
We know that $\sqrt 64=8$, because $8^{2}=64$.
Intermediate Algebra (12th Edition)
by Lial, Margaret L.; Hornsby, John; McGinnis, Terry
Published by
Pearson
ISBN 10:
0321969359
ISBN 13:
978-0-32196-935-4
Chapter R - Section R.3 - Exponents, Roots, and Order of Operations - R.3 Exercises - Page 30: 82
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