Answer
16
Work Step by Step
We are asked to evaluate $z^{2}$, where $z=-4$.
$z^{2}=(-4)^{2}=(-4\times-4)=16$
The numbers being multiplied have the same sign, so the resulting product will be positive.
Intermediate Algebra (6th Edition)
by Martin-Gay, Elayn
Published by
Pearson
ISBN 10:
0321785045
ISBN 13:
978-0-32178-504-6
Chapter 1 - Sections 1.2-1.3 - Integrated Review - Algebraic Expressions and Operations on Whole Numbers - Page 29: 1
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