Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 1 - Sections 1.2-1.3 - Integrated Review - Algebraic Expressions and Operations on Whole Numbers - Page 29: 2

Answer

-16

Work Step by Step

We are asked to evaluate $-z^{2}$, where $z=-4$. $-z^{2}=-(-4)^{2}=-(-4\times-4)=-(16)=-16$ According to order of operations, we must first evaluate the exponent and then consider the negative sign.
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