Answer
0
Work Step by Step
We are asked to evaluate $\frac{4x-z}{2y}$, where $x=-1$, $y=3$, and $z=-4$.
$\frac{4x-z}{2y}=\frac{(4\times-1)-(-4)}{2\times3}=\frac{-4+4}{6}=\frac{0}{6}=0$
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