Answer
92
Work Step by Step
$8-6[\sqrt[3] 8(-2)+\sqrt 4(-5)]=8-6[(\sqrt[3] 8\times-2)+(\sqrt 4\times-5)]=8-6[(2\times-2)+(2\times-5)]$
To simplify the expression, first perform the operations within parentheses.
$8-6[(2\times-2)+(2\times-5)]=8-6[(-4)+(-10)]$
Next, perform the operation in brackets.
$8-6[-(4+10)]=8-6[-14]$
Finally, perform the remaining operations.
$8-(6\times-14)=8-(-84)=8+84=92$
Notes:
We know that $\sqrt[3] 8=2$, because $2^{3}=2\times2\times2=8$
and that $\sqrt 4=2$, because $2^{2}=2\times2=4$
