Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.5 - Problem Solving and Using Formulas - Exercise Set - Page 66: 11

Answer

$$x = 2$$

Work Step by Step

$y_{1} = 13x - 4$ equation 1 $y_{2} = 5x + 10$ equation 2 $y_{1}$ exceeds $y_{2}$ by 2 --> $y_{1}$= $y_{2}$ +2 equation 3 Substitute equations 1 & 2 to equation 3: $$(13x - 4) = (5x + 10) +2$$ Remove the parentheses: $$13x - 4 = 5x + 10+2$$ $$13x - 4 = 5x + 12$$ Add 4 to both sides: $$13x - 4 +4 = 5x + 12 + 4$$ $$13x = 5x + 16$$ Simplify: $$8x = 16$$ Divide both sides by 8 $$x = 2$$
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