Answer
$x=8$
Work Step by Step
$y_{1}=10(2x - 1)$ equation 1
$y_{2}=2x + 1$ equation 2
$y_{1}$ is 14 more than 8 times $y_{2}$ --> $y_{1} = 14+8y_{2}$ equation 3
Substitute equations 1 & 2 to equation 3, $y_{1} = 14+8y_{2}$:
$10(2x - 1)= 14+8(2x + 1)$
Expand $10(2x - 1)$ = $20x-10$
Expand $8(2x + 1)$ = $16x+8$
Rewrite the equation:
$20x-10 = 14 + 16x+8$
$20x-10 = 22 + 16x$
Add 10 to both sides:
$20x-10+10 = 22 +10 + 16x$
$20x = 32 + 16x$
Simplify:
$4x = 32$
Divide both sides by 4:
$x=8$
