Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.5 - Problem Solving and Using Formulas - Exercise Set - Page 66: 20

Answer

Angles (in order: 1st, 2nd, 3rd): $129^{\circ},\ 43^{\circ},\ 8^{\circ}$

Work Step by Step

From the text, we build expressions relating the angles: $\left[\begin{array}{lll} \text{ 1st angle, } A & = & 3B\\ \text{ 2nd angle, } B & = & B\\ \text{ 3rd angle, } C & = & B-35^{\circ} \end{array}\right.$ $ A+B+C=180^{\circ}\qquad$... sum of angles is $180^{\circ}$ ... replace A and C with corresponding expressions $ 3B+B+B-35^{\circ}=180^{\circ}\qquad$... solve for B $5B-35=180^{\circ}$ $5B=215^{\circ}$ $B=43^{\circ}$ Back substitute: $A=3B=129^{\circ}$ $C=B-35^{\circ}=8^{\circ}$ Angles (in order: 1st, 2nd, 3rd): $129^{\circ},\ 43^{\circ},\ 8^{\circ}$
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