Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 1 - Section 1.5 - Problem Solving and Using Formulas - Exercise Set - Page 66: 14

Answer

$x=2$

Work Step by Step

$y_{1}=9(3x - 5)$ equation 1 $y_{2}=3x - 1$ equation 2 $y_{1}$ is 51 less than 12 times $y_{2}$ --> $y_{1}=12y_{2} - 51$ equation 3 Substitute equations 1 & 2 to equation 3, $y_{1}=12y_{2} - 51$: $9(3x - 5)=12(3x - 1)-51$ Expand $9(3x - 5)$ = $27x-45$ Expand $12(3x - 1)$ = $36x-12$ Rewrite the equation: $27x-45 = 36x-12 - 51$ $27x-45 = 36x-63$ Add 45 to both sides: $27x-45+45 = 36x-63+45$ $27x = 36x - 18$ Simplify: $-9x = -18$ Divide both sides by -9: $x=2$
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