Answer
$4^{-2} =\dfrac{1}{4^2}=\dfrac{1}{16}$
Work Step by Step
RECALL:
The negative-exponent rule of exponents states that:
$a^{-m} = \dfrac{1}{a^m}$ or $\dfrac{1}{a^{-m}} = a^m$, where $a \ne 0$.
Use the negative-exponent rule to find:
$4^{-2} =\dfrac{1}{4^2}=\dfrac{1}{16}$
