Answer
$x^3y^{-4} =\dfrac{x^3}{y^4}$
Work Step by Step
RECALL:
The negative-exponent rule of exponents states that:
$a^{-m} =\dfrac{1}{a^m}$ and $\dfrac{1}{a^{-m}} = a^m$, where $a \ne 0$.
Use the negative-exponent rule to find:
$x^3y^{-4} = x^3 \cdot \dfrac{1}{y^4}=\dfrac{x^3}{y^4}$
