Answer
$x^2y^{-3}=\dfrac{x^2}{y^3}$
Work Step by Step
RECALL:
The negative-exponent rule of exponents states that:
$a^{-m} =\dfrac{1}{a^m}$ and $\dfrac{1}{a^{-m}} = a^m$, where $a \ne 0$.
Use the negative-exponent rule to find:
$x^2y^{-3} = x^2 \cdot \dfrac{1}{y^3}=\dfrac{x^2}{y^3}$