Answer
$8x^{-7}y^{3} =\dfrac{8y^3}{x^7}$
Work Step by Step
RECALL:
The negative-exponent rule of exponents states that:
$a^{-m} =\dfrac{1}{a^m}$ and $\dfrac{1}{a^{-m}} = a^m$, where $a \ne 0$.
Use the negative-exponent rule to find:
$8x^{-7}y^{3} = 8 \cdot \dfrac{1}{x^7} \cdot y^3 =\dfrac{8y^3}{x^7}$
