Answer
See image
Work Step by Step
Approximately, $T(e_1)=\begin{bmatrix}
-5\\
2
\end{bmatrix}$ and $T(e_2)=\begin{bmatrix}
9\\
2
\end{bmatrix}$. Therefore, $A=\begin{bmatrix}
-5&9\\
2&2
\end{bmatrix}$
$T(2,1)=\begin{bmatrix}
-5&9\\
2&2
\end{bmatrix}\begin{bmatrix}
2\\
1
\end{bmatrix}=\begin{bmatrix}
-1\\
6
\end{bmatrix}$
Please note this is an approximate, not exact, solution.
