Linear Algebra and Its Applications (5th Edition)

Published by Pearson
ISBN 10: 032198238X
ISBN 13: 978-0-32198-238-4

Chapter 1 - Linear Equations in Linear Algebra - 1.9 Exercises - Page 79: 22

Answer

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Work Step by Step

\[ T(\mathbf{x})=\left[\begin{array}{c} x_{1}-2 x_{2} \\ -x_{1}+3 x_{2} \\ 3 x_{1}-2 x_{2} \end{array}\right]=A\left[\begin{array}{c} x_{1} \\ x_{2} \end{array}\right]=\left[\begin{array}{cc} 1 & -2 \\ -1 & 3 \\ 3 & -2 \end{array}\right]\left[\begin{array}{l} x \\ x \end{array}\right] \] So \[ T(\mathbf{x})=\left[\begin{array}{c} -1 \\ 4 \\ 9 \end{array}\right] \] row decrease the augmented matrix: \[ \left[\begin{array}{ccc} 1 & -2 & -1 \\ -1 & 3 & 4 \\ 3 & -2 & 9 \end{array}\right] \] Augmented Matrix \[ \left.\begin{array}{ccc} 1 & -2 & -1 \\ 0 & 1 & 3 \\ 0 & 4 & 12 \end{array}\right] \] $\left[\begin{array}{lll}1 & 0 & 5 \\ 0 & 1 & 3 \\ 0 & 0 & 0\end{array}\right]$ $R_{1}=R_{1}+2 R_{2}$ $\mathbf{x}=\left[\begin{array}{l}5 \\ 3\end{array}\right]$
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