Answer
$\lim\limits_{x\to0}\dfrac{3(1-\cos{x})}{x}=3.$
Work Step by Step
Using Theorem $1.9$:
$\lim\limits_{x\to0}\dfrac{3(1-\cos{x})}{x}=3\lim\limits_{x\to0}\dfrac{1-\cos{x}}{x}=3(0)=0.$
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